Write the log equation as an exponential equation. You do not need to solve for x. log (x^2– 5x + 14) = 2x + 4

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  x^2 -5x +14 = 10^(2x +4)

Step-by-step explanation:

The relationship is ...

  log(a) = b   ⇔   a = 10^b

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Using this with a=x^2-5x+14 and b=2x+4, we have ...

  x^2 -5x +14 = 10^(2x +4)

Additional comments

In plain text, the exponent needs parentheses, because superscript formatting is not available to tell what is and isn't part of the exponent.

The base of "log" is assumed to be 10 in high school algebra. In the larger world, "log" is often used in place of "ln" to mean the logarithm to base 'e'.

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The one solution is approximately x = −1.32505947996.

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

he kicked it up? is this the answer ?

step-by-step explanation: