Find the inverse of the following function. g(x) = 1/x - 2 plz show work

A.) g^-1(x) = - 2/x-1

B.) g^-1(x) = 2/x-1

C.)g^-1(x) = 1/x+ 2

D.) g^-1(x) = 2/x+1

C. g^(-1) (x)= 1/(x+ 2)

Step-by-step explanation:

y=1/x-2

x=1/y-2

1/y-2=x

1/y=x+2

1=(x+2)y

1=xy+2y

xy+2y=1

(x+2)y=1

y=1/(x+2)

g^(-1) (x)= 1/(x+ 2)

answer is

c) 4

step-by-step explanation:

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1