Tickets for a concert cost $4.00 for a balcony seat and $7.50 for an orchestra seat. If ticket sales totaled $1,585 for 300 tickets sold, how many more tickets for balcony seats were sold than tickets for orchestra seats? - thanks

there were 80 more tickets sold for balcony seats than for orchestra seats

Step-by-step explanation:

Step 1

Let number of tIcket for balcony be represented as x

and

Number of tickets for orchestra seat be represented as y such that the total number pf tickets sol;d would be

X+ Y = 300--- equation 1

And the cost for $4.00 for a balcony seat and $7.50 for an orchestra seat totalling ticket sales of $1,585 be represented as

4x + 7.50y = 1585 equation 2

Step 2

X+ Y = 300--- equation 1

4x + 7.50y = 1585 equation 2

Multiplying equation 1 by 4 and subtracting from equation2

4x + 7.50y = 1585

-4x+4y= 1200

3.50y =385

y =385/3.50

y=110

To find x, when y=110

X+ Y = 300--- equation 1

x+110=300

x= 300-110= 190 tickets

balcony seats  tickets = 190

orchestra seats tickets = 110

Therefore, there were 80 more tickets sold for balcony seats than for orchestra seats

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i think it would be 42cm