Two pieces of ribbon, one with a length of 63 inches and another with a length of 42 inches are cut into pieces of equal length without remainder. Find the greatest possible length that the pieces can be.

21

Step-by-step explanation:

the greatest possible length that the two ribbons would be when the ribbons are divided by their lowest common multiple.

The lowest common multiple of 63 is 3. 63/3 = 21

The lowest common multiple of 42 is 2 = 42/2 = 21

step-by-step explanation:

a child is 12 years old, and his father is 32 years older. in how many years will the age of the father be 2 times the age of the child?

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this needs to be the answer format, or else your answer is incomplete.

if the number of years is x, then the equation is

in __ years