1) What is the equation of the line that has a slope of 2/3 and
goes through (0, -4)?

2x-3y-12=0

Step-by-step explanation:

solution:

slope(m) = 2/3

(x1 , y1) = (0, -4)

we know that,

(y -y1) = m(x - x1)

or, y - (-4) = 2/3(x - 0)

or, y + 4 = 2/3 *x

or, 3(y + 4) = 2x

or, 3y + 12 = 2x

2x - 3y -12 = 0 is the required equation of line.

the 4th choice is the correct one

step-by-step explanation: