What is the equation of the line that passes through the point (4,11) and is perpendicular to the line with the following equation? Y=4/3x+7

Step-by-step explanation:

y = (4/3)x+7

Slope of the line is 4/3.

Slope of any perpendicular to the line is -¾.

Point-slope equation for line of slope -¾ that passes through (4,11):

y-11 = -¾(x-4)

Of course, you may want to rearrange it to slope-intercept form or standard form.

y = -¾x+15 slope-intercept

x+4y = 60 standard

step- i d k and i d c : )

you: : 0

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