The speed ( in knots) of sound waves in air can be modeled by v(k) = 643.855
k
273.15
Where K is the air temperature (in Kelvin). The speed (in meters per second) of sound waves in the air
can be modeled by
s(K)
v(K)
1.944
What is the speed (in meters per second) of sound waves when the air temperature is 305 Kelvins?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

c

step-by-step explanation: