Answers: 1
Mathematics, 21.06.2019 14:30
Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.
Answers: 3
Mathematics, 21.06.2019 15:30
Write the expression in simplified radical form. show all steps and work including any foil method work. (hint: use the conjugate. no decimal answers.) (9-2√3)/(12+√3)
Answers: 1
Is (-4,-6) a solution?
2x + 3y <-9
x - 2y 2 - 4
(-4, -6)...
2x + 3y <-9
x - 2y 2 - 4
(-4, -6)...
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