A student jogged at a constant rate of 7 miles per hour for 1 1/3
hour. The function d = 7t can be used to find the
distance in miles the student jogged during t, the time in hours.
What is the range of the function for this situation?

A - 0_< t _< 1/3

B - {0,7/3}

C - 0_< d _< 7/3

D - {0,1/3}

C

Step-by-step explanation:

i did it and it’s c the one with 0<_d<_ 7/3

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

b

step-by-step explanation: