PLEASE HELP DUE IN 5 MIN... Carson has a smart phone data plan that costs $40 per month that includes 2 GB of data, but will charge an extra $10 per GB over the included amount. How much would Carson have to pay in a month where he used 3 GB over the limit? How much would Carson have to pay in a month where he used went over by xx GB?

a. $70

b. $(40 + 10x)

Step-by-step explanation:

The standard cost of the charges is $40 per month but an extra $10 per GB over the included amount.

a. Firstly the cost for a month in which he uses 3GB over the limit

we have a standard of $40, then he has to pay $10 per GB for the 3GB over the limit.

Thus the cost of the 3GB is $10 * 3 = $30

The total cost for using 3GB above the limit would be $40 + $30 = $70

b. For using x GB above the limit

He has to pay $10 per each GB above the limit

Thus, the amount to be paid for x GB above the limit would be x * $10 = $10x

So the total amount to be paid would be the base fee plus over the limit fee= $(40 + 10x)

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: