A smokestacks, AB, is 55 m high. From two points C and D on the same side of the smokestack’s base B, the angles of elevation to the top of the smokestack are 40 degrees and 36 degrees repectively. Find the distance between C and D to the nearest metre. Plz guys help me with this question ASAP

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CD=10.15m

Step-by-step explanation:

Find the distance of BC.

Tan(40)=55/BC

BC=65.55m

Find the distance of BD.

Tan(36)=55/BD

BD=75.70m

Use BC and BD to find CD

BD-BC=CD

75.70-65.55=CD

CD=10.15m

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