Solve the following system of equations.
2x+y=3
I= 2y - 1
x=
y=

Note: I am assuming your second equation is:

x = 2y - 1

The solution to the system of equations is:

Step-by-step explanation:

Given the system of equations

2x+y=3

x = 2y - 1

solving the system of equations using the elimination method

Arrange equation variables for elimination

Multiply x-2y=-1 by2:     2x-4y=-2

subtracting the equations

now solve -5y = -5 for y

Divide both sides by -5

Simplify

For 2x+y=3 plug in y=1

subtract 1 from both sides

Simplify

Divide both sides by 2

Simplify

Therefore, the solution to the system of equations is:

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

answer: what in the world is this

step-by-step explanation: