When using the inspection method, the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x+ 3) as a factor is

Question:

Consider the expression

When using the inspection method the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is?

The constant to add is 4

Step-by-step explanation:

Given

First, we need to get an expression that has x + 3 has its factor.

Represent this expression with:

Expand

Group like terms

Compare the above expression to:

However, we only consider solving for k

Subtract 3 from both sides

Substitute -2 for k in

So, the expression that has a factor of x + 3 is

To get the constant term to add/subtract, we have:

Open brackets

Collect Like Terms

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .