If h(x) = (fog) (x) and h(x)=4(x+1)^2, find f(x) and g(x)

a. f(x) = 4x^2
g(x) = (x+1)^2

b. f(x) = 4x^2
g(x) = x+1

c. f(x) = x+1
g(x) = 4x^2

d. f(x) = (x+1)^2
g(x) = 4x^2

x= 3^y

step-by-step explanation:

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function