A dilation has center (0,0). Find the image of the point LC-5,0) for the scale factor 8.

The image of the point C(-5,0) for the scale factor 8 is: C'(-40, 0)

Step-by-step explanation:

Given the coordinates of the point

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

Rule to calculate the dilation by a scale factor 8 centered at the origin

P(x, y) → P'(8x, 8y)

Here, P'(8x, 8y) is the image of P(x, y).

It means the coordinates of the image can be determined by multiplying the coordinates of the original point by 8.

Thus,

C(-5, 0) → C'(8(-5), 8(0)) = C'(-40, 0)

Therefore,

The image of the point C(-5,0) for the scale factor 8 is: C'(-40, 0)

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)