A family has two children. Find the probability that both children are girls, given that at least one of the two is a girl who was born in winter. Please assume that (i) gender is binary, i. e., a boy or a girl, (ii) P (a boy) = P (a girl) = 1/2, (iii) genders of the two children are independent, i. e., knowing one’s gender gives no information about the other’s gender, (iv) four seasons are equally likely, and (v) gender is independent of season.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.