the sail area-displacement ratio S is given by S= 16A/d^2/3, where A is the sail area (ft^2) and d is the displacement (lb). S measures the amount of power available to drive a sailboat. Ratios range from 24 to 35, with a high ratio indicating a powerful boat. Find S for the sailboat, which has a displacement of 1400 tons, a sail area of 42400 ft^2, and 49 guns. What is the sail area-displacement ratio S = ?

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)