Please solve the problem in the attachment.
It is due on thursday.

A= 7

B= 8

C= 3

Step-by-step explanation:

For C: 9=C*C-->C=SQRT(9)=3

For B: Some number ending in 4 is equals to B*C, C being 3. Then, the first number that fits that criteria would be B=8, as B*C=8*3=24.

For C: Some number ending in 1 equals to A*C. Then, the first number that fits that criteria is A=7, as A*C=7*3=21.

If you now multiply ABC*ABC (783*783) you'll see that all the elements in the multiplication process as carried out in the pdf are non-zero, so our answer satisfies the conditions of the problem!

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: