Question #18 In order to save money for prom, Tom is going to walk his
neighbor's dog for $6 an hour and wash cars for $7.50 an
hour. His mother told him he is not allowed to work more
than 15 hours in order to keep up with his homework. If
Tom would like to make at least $75 to cover prom
expenses, help him determine combination of hours he can
work between the 2 jobs.
A. Write and graph a system of linear inequalities.
B. What are 2 possible solutions? (see choices below)
4 hrs dog walking & 8 hours car washing
3 hrs dog walking & 4 hours car washing
10 hrs dog walking & 3 hours car washing
12 hrs dog walking & 4 hours car washing

A) I cannot really put a graph here but it should be something like 6x+7.5y> or = 75, x+y < or = 15

B)Choice 1 and 3

Step-by-step explanation:

For part A we can say that x is how many hours he walks his neighbor's dogs and y for how many hours he washed cars and set up equation so that he gets more than 75 dollars and less than 15 total hours. For part B, the last choice can be eliminated because it exceeds total of 15 hours, choice 2 can be eliminated because it does not reach a 75 dollars if you use the value of x and y in the equation in part A, therefore answers are choice 1 and 3.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

hdjd

step-by-step explanation: