Television sizes are measured on the diagonal Tony's television length is 42 inches and the television width is 31 inches what is the diagonal measurement of Tony's television rounded to the nearest inch

52 in approx

Step-by-step explanation:

Given data

Length of TV= 42 in

Widht of TV= 31 in

Required

The diagonal of the TV

Applying the Pythagoras theorem

D^2= L^2+W^2

D= √L^2+W^2

D= √42^2+31^2

D=√1764+961

D=√2725

D=52.20 in

Hence the diagonal of the Tv is 52 in approx

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

ratio is 2 : 9

the answer is three

13.5 : 3