In a jumping contest between three frogs—Cal, Sunny, and Legs—each complete two jump/step sequences that land them in the same place.** When Cal jumps 3 times and then takes 6 steps forward, he lands in the same place as when he jumps 4 times and then takes 2 steps backward. When Sunny jumps 4 times and then takes 11 steps forward he lands in the same place as when he jumps 5 times and then takes 4 steps forward. When Legs jumps 2 times and then takes 13 steps forward he lands in the same place as when he jumps 4 times and then takes 5 steps backward. Which frog has the biggest jump (and wins the contest)?

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation:

1/4 is the answer if i recall correctly.