PLEASE HELP ME!! let g be the function given by g (x) = 3x^4 - 8x^3. At what value of x on the closed interval [ -2,2 ] does g have an absolute maximum

The value of x on the closed interval [ -2,2 ] that g has an absolute maximum is 0

Given the function

The function is at a maximum at g'(x) = 0

Differentiating the function given:

Substitute x = 0 and x = 2 into the function;

g(0) = 3(0)^3 - 8(0)^3

g(0) = 0

Since the range of the function is least at x = 0, hence the value of x on the closed interval [ -2,2 ] that g has an absolute maximum is 0

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u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w