Members of the band are selling candy bars to raise money. The director uses this equation to calculate the amount of profit, p, made from selling n candy bars. p = 1.50n – 500 How many candy bars must be sold to make a profit of $700? *

800 candy bars must be sold to make a profit of $700

Step-by-step explanation:

Members of the band are selling candy bars to raise money

The director uses this equation to calculate the amount of profit p,

made from selling n candy bars p = 1.50 n - 500

We need to find the number of candy bars must be sold to make

a profit of $700

1. Write the equation

2. substitute p by 700

3. solve to find n

∵ p = 1.50 n - 500

∵ p = $700

∴ 700 = 1.50 n - 500

- Add 500 for both sides

∴ 1200 = 1.50 n

- Divide both sides by 1.50

∴ n = 800

∴ The number of the candy bars is 800

800 candy bars must be sold to make a profit of $700

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2