A boy and his friend wish to calculate the height of a flagpole. One boy holds a yardstick vertically at a point 40 feet from the base of a flagpole, as shown. The other boy backs away from the pole to a point where he sees the top of the flagpole over the top of the yardstick. If his position is 1 foot 9 inches from the yardstick and his eye level is 2 feet above the ground. Find the height of the flagpole in inches. Round to the nearest whole inch.

One boy holds a yardstick vertically at a point 40 feet from the base of the flagpole. The other boy backs away from the pole to a point where he sights the top of the pole over the top of the yardstick. If his position is 1 ft 9 in from the yardstick and his eye level is 2 ft above the ground, find the height of the flagpole.

Hello,

Did you draw a diagram?

Flag pole

The second boy's eye, the top of the yard stick and the top of the flagpole form a straight line. I extended this line to meet the ground at E and called the distance the second boy to the ground |DE| = x feet.

The triangles GCE and FDE are similar and hence

|CE|/|GC| = |DE|/|FD|

(1' 9" + x')/3' = x'/2'

But 1' 9" = 1.75' and hence you can solve the above equation for x.

Now use the fact that triangles ABE and FDE are similar to find h.

Chase-

Step-by-step explanation:

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted