What are the solutions of 16p^2 - 64 = 0

p = 2 or p = -2

Step-by-step explanation:

Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

|  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

|  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

|  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

p = 2 or p = -2

there is no question content here, but you for the free points! : d

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step-by-step explanation: