The height of a male athlete testing his vertical jump can be modeled by h = − 16t ^2 + 14t. The height is h and the time is t. How many seconds is he in the air?

0.88 (I think this is how Mrs. Futch wants it to be written)

Step-by-step explanation:

h=-16t^2+14t

(Substitute h with 0)

0=-16t^2+14t

(Factor)

0=2t(-8t+7)

2t=0               -8t+7=0

t=0                  t=0.88

{0, 0.88}

(John Komperda)

what graph

step-by-step explanation: