Help me with this question please please
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If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then
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Sh what is the value of x? ox= 2.25 x = 11.25 ox= x = 22 1 (2x + 10) seo - (6x + 1) -- nie
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Simplify (4x^2 - 8xy + 2y^2) - (9x^2 - 4xy - 7y^2) a. -5x^2 + 4xy + 9y^2 b. -5x^2 - 4xy + 9y^2 c. -5x^2 + 12xy + 4y^2 d. -5x^2 - 4xy - 5y^2
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