A club is going to raise money by printing calendars with photos of the community. The cost of printing the calendars is $5.50 per calendar. The photographer also charges a one-time cost of $200 for taking the photos. The club has $1500 to cover the initial costs of the calendar. Create an equation that represents the number of calendars the club can print. Use the variable n for the number of calendars

Step-by-step explanation:

Given

The cost of printing one calendars dollars

The one time charge of taking photo dollars

The total sum of money with the club dollars

The total sum of money going into printing of calendars dollars

The total number of calendars that can be printed with remaining dollars is equal to

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

right

step-by-step explanation: