Find the first five terms of the recursive sequence.

The first five terms of the recursive sequence are;

5, 12, 19, 26, 33

Step-by-step explanation:

The given sequence is presented as follows;

aₓ = a₍ₓ ₋ ₁₎ + 7

The first term of the sequence, a₁ = 5

Therefore, we have;

a₂ = a₍₂ ₋ ₁₎ + 7 = a₁ + 7 = 5 + 7 = 12

a₃ = a₍₃ ₋ ₁₎ + 7 = a₂ + 7 = 12 + 7 = 19

a₄ = a₍₄ ₋ ₁₎ + 7 = a₃ + 7 = 19 + 7 = 26

a₅ = a₍₅ ₋ ₁₎ + 7 = a₄ + 7 = 26 + 7 = 33

The first five terms of the recursive sequence are therefore;

5, 12, 19, 26, 33.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: about 22.67

step-by-step explanation: