∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the height from C to AB i. e., CE

I have attached an image of the triangle.

BC = 9 cm

CE = 7.2 cm

Step-by-step explanation:

In the attached triangle, we see that;

AB = AC = 7.5cm

BC = 9 cm

AD = 6cm

BC = 9cm

Formula for area of triangle is given as;

A = ½bh

Where b is base and h is height.

For the ∆ ABC with BC as base,

Area = ½ × 9 × 6 = 27 m²

Similarly, For ∆ ABC with AB as base,

Area = ½ × 7.5 × CE

Now, area from earlier is 27 cm²

Thus;

½ × 7.5 × CE = 27

Multiply both sides by 2 to get;

7.5CE = 54

CE = 54/7.5

CE = 7.2 cm

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x