1. Gabriel has a candy box containing 9 chocolates candies and 12 lollipops. If he choose 2 of them at random. a) What is the probability that he gets 2 lollipops?
b) What is the probability that he gets 2 chocolates?
c) What is the probability that he gets at least 1 lollipop and 1 chocolate?

Question :

Gabriel has a candy box containing 9 chocolates candies and 12 lollipops. If he choose 2 of them at random.

a) What is the probability that he gets 2 lollipops?

b) What is the probability that he gets 2 chocolates?

c) What is the probability that he gets at least 1 lollipop and 1 chocolate?

Answer:

First we need to calculate the total no. of items. In this case it is the no. of chocolate candies + the no. of lollipops which is, 9 + 12 = 21.

Now we can solve the questions.

a) P (2 lollipops) = 2/21.

b) P (2 chocolates) = 2/21.

c) P (at least 1 lollipop & 1 chocolate) = 2/21.

Note : P(x) is read as probability of getting x is

Question :

Gabriel has a candy box containing 9 chocolates candies and 12 lollipops. If he choose 2 of them at random.

a) What is the probability that he gets 2 lollipops?

b) What is the probability that he gets 2 chocolates?

c) What is the probability that he gets at least 1 lollipop and 1 chocolate?

Answer:

First we need to calculate the total no. of items. In this case it is the no. of chocolate candies + the no. of lollipops which is, 9 + 12 = 21.

Now we can solve the questions.

a) P (2 lollipops) = 2/21.

b) P (2 chocolates) = 2/21.

c) P (at least 1 lollipop & 1 chocolate) = 2/21.

Note : P(x) is read as probability of getting x is

A)21/2

b)21/2

3)21/2

Step-by-step explanation:

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x