The 10th, 4th and 1st term of an A. P are three consecutive find the common ratio of the G. P and the sum of the 6th term, taking the 1st term to be 4

Common ratio=1/2

Sum of first 6 terms of an A.P=31.5

Step-by-step explanation:

Let a be the first term and d be the common difference of an A.P

a=4

nth term of an A.P

Using the formula

According to question

We know that

For G.P

=Common ratio

Substitute the value of d

When d=0

When d=4/3

But we reject d=0 because  if we take d=0 then the terms are not consecutive terms of G.P

Sum of n terms of an A.P

Using the formula

Substitute n=6 and d=1/2

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation:

using pemdas, (order of operations) you'll see the answer is 24.