Emir flew home from vacation with a heavy bag. With the first airline he flew, Emir had to pay $20 to check his bag, plus $10 for every pound that his bag was over the weight limit. The next flight was with another airline that had the same weight limit. Emir had to pay $5 per pound that his bag was over the weight limit, in addition to the checked bag fee of $30. By coincidence, the fees ended up being the same with both airlines. How large was each airline's fee?

$27.5

Step-by-step explanation:

Let

x = pound over weight limit

Airline 1 = 20 + 10x

Airline 2 = 5 + 30x

Equate the fees

20 + 10x = 5 + 30x

20 - 5 = 30x - 10x

15 = 20x

x = 15/20

x = 0.75 pounds

How large was each airline's fee?

Airline 1 = 20 + 10x

= 20 + 10(0.75)

= 20 + 7.5

= $27.5

Airline 2 = 5 + 30x

= 5 + 30(0.75)

= 5 + 22.5

= $27.5

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

your answer is the frist one

hop i