How many multiples of 5 are there in between 100 and 300?

Solution given:

first term [a]=100

last term[l]=300

common difference [d]=5

second term[b]=100+5=105

now

we have

l=a+(n-1)d

substituting value

300=100+(n-1)5

300-100=(n-1)5

200/5=n-1

40=n-1

n=40+1

there are 41 multiple in between 100 and 300/including it but no including its 41-2=39 multiple

Step-by-step explanation:

Consider AP:

As multiples of 5 between 100 and 300

The first term is 105, the common difference is 5, the last term is 295.

Use the nth term formula:

5x+10 is the correct one

hope this