a frog sits at a number line at point -10. it is allowed to make up to 4 jumps. first, it can make a jump of 8 units in either direction, or it can skip this jump. then, it can make a jump 4 units long or skip this jump. then, it can make a jump two units long or skip this jump. and finally, it can make a jump one-unit long or skip this jump. where can it be at the end?

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%