P(x) = x3 - 2x2 + 2x
What are the real and complex zeros of the equation

Given:

The polynomial is

To find:

The real and complex zeros of the equation.

Solution:

We have,

For zeros, p(x)=0.

The real value of x is 0. The equation will give complex roots. Here, a=1, b=-2 and c=2.

Using quadratic formula, we get

On further simplification, we get

Therefore, the real zero is 0 and the complex zeros are 1+i and 1-i.

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right