Below is a table of the breaking strength in pounds of 20 pieces of Douglas fir.33,19031,86032,59026,52033,2803 2,32033,02032,03030,46032,70023,040 30,93032,72033,65032,34024,05030,17 031,30028,73031,920Give the five-number summary of the distribution of breaking strengths. Match your results below. Make sure that you calculate the quartiles manually exactly as defined in the text. Do not rely on results from calculators or software since they may use alternative definitions for the quartiles.1. 23,0405. 31,8609. 32,030 13. 32,46517. 32,7002. 26,5206. 31,89010. 32,32014. 32,59018. 32,7203. 30,3157. 31,92011. 32,33015. 32,64519. 33,0204. 30,4608. 31,97512. 32,34016. 32,71020. 33,650Enter the number of the term that corresponds to each choice:MinimumQ 1MedianQ 3Maximum

Minimum = 23,040

Q1 = 30315

Q2 = 31975

Q3 = 31975

Maximum = 33650

Step-by-step explanation:

Ordered data:

23040, 24050, 26520, 28730, 30170, 30460, 30930, 31300, 31860, 31920, 32030, 32320, 32340, 32590, 32700, 32720, 33020, 33190, 33280, 33650

The five number summary :

Minimum = 23,040

Lower quartile (Q1) = 1/4(n+1)th term

n = 20

Q1 = 1/4* (21)th term

Q1 = 5.25 ; (5th + 6th) term / 2

Q1 = (30170 + 30460) / 2 = 30315

Median (Q2) :

Q2 = 1/2* (21)th term

Q2 = 10.5 ; (10th + 11th) term / 2

Q2 = (31920 + 32030) / 2 = 31975

Upper Quartile (Q3) :

Q3 = 3/4* (21)th term

Q3 = 15.75 ; (15th + 16th) term / 2

Q 3 = (32700 + 32720) / 2 = 32710

Maximum : 33650

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3