A large discount store wants to determine the average yearly income of its shoppers. A researcher chooses 100 shoppers at random between 1:00 p. m. and 5:00 p. m. on a Saturday to survey. Identify the population. A. All shoppers at the discount store between 1:00 p. m. and 5:00 p. m. on this particular Saturday.
B. The 100 surveyed shoppers at the discount store between 1:00 p. m. and 5:00 p. m. on this particular Saturday.
C. All shoppers at the discount store on this particular Saturday.
D. All shoppers at the discount store during a year's time.
E. None of the above.

The population is:

D. All shoppers at the discount store during a year's time.

Step-by-step explanation:

Since the discount store wants to determine the average yearly income of its shoppers, the population of interest here is all the shoppers that visit the discount store during a year's time.  The population includes all the individual shoppers.  However, this number may be too difficult to obtain and work on their data.  This is the researcher can choose a sample, calculating its statistics to approximate the population parameters.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: