Given: \overline{AC} AC

and \overline{DB}

DB

bisect each other

Prove: \triangle ABE \cong \triangle CDE△ABE≅△CDE.

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

AD = CD      BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°(  )}

AD ≅ CD              ……….{  }

ΔABD  ≅ ΔCBD   ….{By Side-Angle-Side Congruence test}  ...Proved

I think this is it? Hope it helps :)

%40

step-by-step explanation:

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: