A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

56.7°

Step-by-step explanation:

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

We solve this question using the Trigonometric function of Sine

From the question, we are told that:

A rectangle is 5.1 cm wide

and each diagonal is 9.3 cm long.

Since we have a diagonal, this means the shape is transformed to a triangle.

The width of the rectangle = Adjacent side of a triangle = 5.1cm

The diagonal of the rectangle = Hypotenuse = 9.3cm

Hence,

cosθ = Adjacent/Hypotenuse

cosθ = 5.1/9.3

cosθ = 0.5483870968

θ = arccos(0.5483870968)

θ = 56.743568714°

Approximately = 56.7°

The measure of the angle is 56.7°

let soccer = x and golf = y

part a

1st equation: x + y = 125

2nd equation: x = y +45

part b

replace x in the 1st equation with the 2nd one:

y + 45 + y = 125

simplify:

2y + 45 = 125

subtract 45 from each side:

2y = 80

divide both sides by 2:

y = 80/2

y = 40

she plays golf for 40 minutes.

part c

no because she plays soccer for 45 minutes longer than golf 40 +45 =   85 minutes, not 80 minutes.

answer:

sometimes

*i think