Suppose you have a right triangle area marked in the ground with a base (8-h) meters long and a height h meters long. the hypotenuse is 6 meters long. part a: what is the length of the height of the right triangle

5.415m and 2.585m long

Step-by-step explanation:

For a right triangle

hyp^2 = opp^2 + adj^2 (Pythagoras theorem)

Given

hypotenuse = 6m

height(opposite) = h meters

Adjacent = (8-h)m

Substitute into the expression above;

6² = h²+(8-h)²

36 = h²+64-16h+h²

36 = 2h²-16h+64

2h²-16h+64-36 = 0

2h²-16h+28= 0

Divide through by 2

h²-8h+14 = 0

Using the general formula

h = 8±√8²-4(14)/2

h = 8±√64-56/2

h = 8±√8/2

h = 8±2.83/2

h = 8+2.83/2 and 8-2.83/2

h = 10.83/2 and 5.17/2

h = 5.415 and 2.585

hence the length of the height of the right triangle are 5.415m and 2.585m long

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363