A diver is on a diving board 12 meters above the water. He dives vertically from the board with initial velocity of 4.9 meter/sec. how high will the diver get above the water?

13.225 m

Step-by-step explanation:

Given that :

Initial Velocity, u = 4.9m/s

Acceleration due to gravity, a = - 9.8 m/s² (downward)

Distance, S = - 12

According to the motion equation :

S = ut + 0.5at²

S = 4.9t + 0.5(-9.8)t²

S = 4.9t - 4.9t² - - - (1)

At the highest point, v = 0

v² = u + at

0 = 4.9 + - 9.8t

-9.8t = - 4.9

t = 4.9/9.8

t = 0.5s

Put t = 0.5 in (1) above

S = 4.9(0.5) - 4.9(0.5)²

S = 2.45 - 1.225

S = 1.225 m

Total height :

(12 + 1.225) m = 13.225 m

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

b

step-by-step explanation: