* A Frog sits on a number line at point −10. It is allowed to make up to 4 jumps. First, it can make a jump of 8 units in either direction, or it can skip this jump. Then, it can make a jump 4 units long or skip this jump. Then, it can make a jump 2 units long, or skip this jump. And, finally, it can make a one-unit jump or skip it. Where can it be at the end? The possible numbers where frog could be are from

Answer and explanation:

Assuming the frog jumps from -10 for all jumps, if the frog decides to make all 4 jumps then :

8 units jump= -2 or -18

4 units jump= -6 or -14

2 units jump= -8 or -12

1 unit jump = -9 or -11

If the frog decides to make one jump then skip the others then:

Either it makes 8 units jump= -2 or -18

Or 4 units jump= -6 or -14

Or 2 units jump= -8 or -12

Or 1 unit jump = -9 or -11

If it decides to make 2 jumps and skip the others then:

Either it makes 8 units jump= -2 or -18

and 4 units jump= -6 or -14

Or 2 units jump= -8 or -12

and 1 unit jump = -9 or -11

Or any other mix of units of jump twice

If it decides to make 3 jumps and skip the others then:

Either it makes 8 units jump= -2 or -18

and 4 units jump= -6 or -14

and 2 units jump= -8 or -12

Or 1 unit jump = -9 or -11

and 4 units jump= -6 or -14

and 2 units jump= -8 or -12

Or any other mix of 3 jumps

If it decides to make no jump at all then the frog would remain at -10

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.