In fact, weather on consecutive days depends on similar atmospheric conditions and therefore consecutive days are not independent events. With the weather forecast of the previous exercise, the probability that it rains over the weekend (either Saturday or Sunday) isA. 0.7516B. 0.3758 C. 0.2484D. Because consecutive days are not independent, we cannot compute P(rain both days) with the information given.

Question is incomplete :

The weather forecast for the weekend is a 46% chance of rain for Saturday and a 54% chance of rain for Sunday. If we assume that consecutive days are independent events, What is the probability that it rains over the weekend (either Saturday or Sunday)? Please use 3 decimal places.

In fact, weather on consecutive days depends on similar atmospheric conditions and therefore consecutive days are not independent events.With the weather forecast of the previous exercise, the probability that it rains over the weekend (either Saturday or Sunday) isA. 0.7516B. 0.3758 C. 0.2484D. Because consecutive days are not independent, we cannot compute P(rain both days) with the information given.

0.7516 ;

D.) Because consecutive days are not independent, we cannot compute P(rain both days) with the information given.

Step-by-step explanation:

Let :

Saturday = A ; Sunday = B

P(A) = 0.46 ; P(B) = 0.54

If A and B are independent :

P(AuB) = P(A) + P(B) - P(AnB)

P(AnB) = P(A) * P(B) = 0.46 * 0.54 = 0.2484

P(AuB) = 0.46 + 0.54 - 0.2484

P(AuB) = 0.7516

If A and B are not independent, and how the weather on Saturday affect the weather on Sunday and vice versa. Hence, we cannot compute AuB

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

three-fourths of an hour

36÷48=0.75

0.75=