Q1 - Multiplying both equations Work these simultaneous equations out
on paper and write down your answers.
p =
2p + 3q
= 20
3p + 2q = 20
The cost of 2 bunches of
roses and 3 bunches of
carnations is $26.
9 =
5s + 2t = 41
S =
The cost of 5 bunches of
roses and 4 bunches of
carnations is $51.
2s + 7t = 66
t =
4a + 7b = 78
a =
Find the cost of one bunch of each.
6a + 9 = 108
b
Il
1 bunch of roses is $
5m + 6 = 70
m =
9m + 9n = 117
n =
[8]
1 bunch of carnations is $
Mark it

u bout ugly as   a mf

step-by-step explanation: lol

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

step-by-step explanation:

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