A radio arm saw has a circular cutting blade with a diameter of 10 inches and it spins at 2000rpm if there are 12 cutting teeth per inch on the cutting blade how many teeth cross the cutting surface each second

12565.11 teeth approximately cut cross the cutting surface per seconds.

Step-by-step explanation:

Since the diameter is 10inches, the circumference of the arm saw is 10π (circumference is πd where d is diameter).

The number of teeth on the cutting blade can be gotten by multiplying the diameter by 12 since we have 12 teeth per inch on the arm saw

Number of teeth on saw = 12 x 10π = 120π.

To get the number of teeth that cross the cutting surface in 2000rpm we multiple it by the total number of teeth in just one rpm.

So we have 2000 x 120π. But since we are asked to find it in revolution per seconds then 2000r/m = 2000r/60s ≈ 33.33

Therefore, we have

33.33 x 120π ≈ 12565.11 teeth

the answer is 5636.7

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept