TVs are usually measured as a diagonal distance across the screen for screen measures 15.1 inches in height and 19 inches diagonally what is the width of the screen round to the nearest 10

11.53 inches

Step-by-step explanation:

Given data

Diagonal = 19 inches

Height=  15.1 inches

Let us apply the Pythagoras theorem

D^2= H^2+W^2

substitute

19^2= 15.1^2+W^2

361=228.01+W^2

361-228.01=W^2

132.99= W^2

W=√132.99

W=11.53 inches

Hence the width is 11.53 inches

is there any photos or whatever?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?