Question 6 - PART A The dot plots show the number of points that Kimberly and Jocelyn each scored in the first 10 basketball games. The mean for Kimberly's basketball games is 6.5 points. The mean for Jocelyn's Basketball games is 16.5 points. The mean absolute deviation of both distributions is 2 points. Points Scored by Kimberly Points Scored by Jocelyn : . 4 6 8 10 12 14 16 18 20 Points 4 6 8 10 12 14 16 18 20 Points - - - I points PART A The mean number of points scored by Jocelyn is greater than the mean numbers of points scored by Kimberly. Type your answer.​

a 10 percent increase

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: