Four basketballs and six baseballs cost $44. Five basketballs and four baseballs costs $48. Determine the cost for one basketball and one baseball.

cost for basket ball= $8 and

cost of baseball = $2

Step-by-step explanation:

Step 1

Let the cost of basket ball be represented as x

and cost of  baseball = y          such that

Four basketballs and six baseballs cost $44 will be expressed as

4x+ 6y= 44  --- eqn 1   also

Five basketballs and four baseballs costs $48 will be expressed as

5x+ 4y= 48--- eqn 2

Step 2

Having obtained two expressions we can now sole

4x+ 6y= 44  --- eqn 1

5x+ 4y= 48--- eqn 2

multiplying eqn 1 by 5 and eqn 2 by 4

20x+ 30y =220 eqn 3

20x+ 16y=192eqn 4

subtracting equation 4 from 3   we now have

14y=28

y= 28/14

y=2 = $2

from equation 1

4x+ 6y= 44, putting the value of y=7 to find x

4x+ 6(2)= 44

4x+12= 44

4x= 44-12

4x=32

x= 32/4

x=8=$8

cost for basket ball= $8 and

cost of baseball = $2

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation: