Evaluate this expression -5y^3+5y^2

That would be 
=−5y3−5y

hope this helps :3 

I'm guessing you mean (-5y^3 + 5y^2)/-y, so I will solve that one first:

(-5y^3 + 5y^2)/-y

5y^2 -5y

5y(y - 1)

The solution for the one you typed out exactly however would be:

-5y^2 + 5y^2/-y

-5y^2 - 5y

5y(-y - 1)

Two because two of one thing is two.

She should use 12/3 to measure